[LØST] parse error? hjelp

[elminzter]

ok, nå er jeg ikke helt med her får en parse error og sjønner ikke hvordan jeg kan få fikse det...

 

får: Parse error: parse error in /web/folk/schouw/zakdotnet/zp_downloads.php on line 20

 

?

 

<div class="ahead">
downloads

<?php
$result = mysql_query("select * from " . $p . " order by category");
while ($entry = @mysql_fetch_object($result)) {
 $name = $entry->name;
 if ($entry->category != $category) {
 	echo('</div><div class="ahead">' . $entry->category . '</div><div class="abody">);
 }
 $category = $entry->category;
 $location = $entry->location;
 $info = $entry->info;
 $ext = $entry->ext;
 $target = "";
 if ($ext == on) {
 	$target = "target=\"_blank\"";
 	$location = "file/" . $location;
 }
 echo('<a href="' . $location . '"); //DETTE ER LINJE 20
 echo($target);
 echo('>' . $name . '</a>');
 if ($ext == "on") {
 	echo(' - file on external site');
 }
 echo('<br>' . $info . '<br>');
}
?>

 

 

for de som lurer:

 

mysql> select * from downloads;

+----+------+----------+----------+----------+------+

| id | name | category | location | info | ext |

+----+------+----------+----------+----------+------+

| 2 | name | stuff | test | external | NULL |

+----+------+----------+----------+----------+------+

 

 

 

hva er galt med echo('<a href="' . $location . '");??

 

 

edit: lenke her om folk vil se der...

Endret 14. april 2006 av elminzter

[rønning]

klipp og lim denne du..

 

 

<div class="ahead">
downloads

<?php
$result = mysql_query("select * from " . $p . " order by category");
while ($entry = @mysql_fetch_object($result)) {
$name = $entry->name;
if ($entry->category != $category) {
 echo('</div><div class="ahead">' . $entry->category . '</div><div class="abody">);
}
$category = $entry->category;
$location = $entry->location;
$info = $entry->info;
$ext = $entry->ext;
$target = "";
if ($ext == on) {
 $target = "target=\"_blank\"";
 $location = "file/" . $location;
}
echo "<a href=\"{$location}\" {$target}>{$name}</a>";
if ($ext == "on") {
 echo(' - file on external site');
}
echo('<br>' . $info . '<br>');
}
?>

[elminzter]

det endte opp med

 

Parse error: parse error in /web/folk/schouw/zakdotnet/zp_downloads.php on line 22

 

 

altså echo(' - file on external site');

 

hva er det som er galt?

[elminzter]

bytta ut med

<div class="ahead">
downloads

<?php
$result = mysql_query("select * from " . $p . " order by category");
while ($entry = @mysql_fetch_object($result)) {
 $name = $entry->name;
 if ($entry->category != $category) {
   echo('</div><div class="ahead">' . $entry->category . '</div><div class="abody">);
 }
 $category = $entry->category;
 $location = $entry->location;
 $info = $entry->info;
 $ext = $entry->ext;
 $target = "";
 if ($ext == on) {
 	$target = "target=\"_blank\"";
 	$location = "file/" . $location;
 }
 echo "<a href=\"{$location}\" {$target}>{$name}</a>";
 if ($ext == "on") {
   echo " - file on external site";
 }
 echo "<br>{$info}<br>";
}
?>

 

og får parse error på linje 26, altså "?>"

 

wtf??

[rønning]

prøv nå da...

 

<div class="ahead">
downloads

<?php
$result = mysql_query("select * from " . $p . " order by category");
while ($entry = @mysql_fetch_object($result)) {
$name = $entry->name;
if ($entry->category != $category) {
echo('</div><div class="ahead">' . $entry->category . '</div><div class="abody">');
}
$category = $entry->category;
$location = $entry->location;
$info = $entry->info;
$ext = $entry->ext;
$target = "";
if ($ext == on) {
$target = "target=\"_blank\"";
$location = "file/" . $location;
}
echo "<a href=\"{$location}\" {$target}>{$name}</a>";
if ($ext == "on") {
echo(' - file on external site');
}
echo('<br>' . $info . '<br>');
}
?>

[elminzter]

prøv nå da...

 

<div class="ahead">
downloads

<?php
$result = mysql_query("select * from " . $p . " order by category");
while ($entry = @mysql_fetch_object($result)) {
$name = $entry->name;
if ($entry->category != $category) {
echo('</div><div class="ahead">' . $entry->category . '</div><div class="abody">');
}
$category = $entry->category;
$location = $entry->location;
$info = $entry->info;
$ext = $entry->ext;
$target = "";
if ($ext == on) {
$target = "target=\"_blank\"";
$location = "file/" . $location;
}
echo "<a href=\"{$location}\" {$target}>{$name}</a>";
if ($ext == "on") {
echo(' - file on external site');
}
echo('<br>' . $info . '<br>');
}
?>

5920171[/snapback]

 

hehe, så det selv at det mangla en ' på echo('</div><div class="ahead">' . $entry->category . '</div><div class="abody">); ^^

 

takker for hjelpen nok en gang rønning